4x^2-4x-49=0

Solution for 4x^2-4x-49=0 equation:

4x^2-4x-49=0

a = 4; b = -4; c = -49;
Δ = b2-4ac
Δ = -42-4·4·(-49)
Δ = 800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{800}=\sqrt{400*2}=\sqrt{400}*\sqrt{2}=20\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-20\sqrt{2}}{2*4}=\frac{4-20\sqrt{2}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+20\sqrt{2}}{2*4}=\frac{4+20\sqrt{2}}{8}
$